Slater's Rule : Effective nuclear charge calculator
Z = Effective nuclear charge; Z = Atomic Number ; σ = Shielding
This online chemistry calculator calculates the effective nuclear charge on an electron. This calculator is based on the Slater's rule of calculating effective nuclear charge. Follow the steps below to calculate effective nuclear charge by the Slater's rule:
Step One : Write down the electronic configuration.
Step Two: Group the electrons in the following way:
(1s) (2s2p) (3s3p) (3d) (4s4p) (4d) (4f) ...
Step Three: Electrons on the right of the one under consideration has no shielding contribution (zero).
Step Four: For each electron in the same group the shielding contribution by each electron will be 0.35 unless it is the 1s orbital. For 1s orbital the shielding contribution by each electron will be 0.30.
Step Five: If the electron under consideration belongs to an s or p orbital then the shielding contribution by the electrons having a principal quantum number less by one would be 0.85 each. And all electrons further left would contribute an amount of 1.0 each.
Step Six : If the electron under considerration belongs to a d or f orbital then the shielding contribution by the electrons on the left would be 1.0 each.
Step One : Write down the electronic configuration.
Step Two: Group the electrons in the following way:
(1s) (2s2p) (3s3p) (3d) (4s4p) (4d) (4f) ...
Step Three: Electrons on the right of the one under consideration has no shielding contribution (zero).
Step Four: For each electron in the same group the shielding contribution by each electron will be 0.35 unless it is the 1s orbital. For 1s orbital the shielding contribution by each electron will be 0.30.
Step Five: If the electron under consideration belongs to an s or p orbital then the shielding contribution by the electrons having a principal quantum number less by one would be 0.85 each. And all electrons further left would contribute an amount of 1.0 each.
Step Six : If the electron under considerration belongs to a d or f orbital then the shielding contribution by the electrons on the left would be 1.0 each.